Demonstrati ca:
a)[tex]( \frac{2a}{a^2-4} - \frac{2}{a-2} + \frac{1}{a+2})/ \frac{a-6}{4(a+2)} = \frac{4}{a-2} [/tex]
b)[tex] \frac{a^2-1}{a^2+1} *( \frac{a}{a-1} - \frac{1}{a+1} )/ \frac{a^2+2a+1}{1-a^2} = \frac{1-a}{a+1} [/tex]

Ajutor rapid,primul raspuns corect dau cel mai bun raspuns si multumesk si 5 stele