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Rezolvati in multimea numerelor naturale, ecuatiile:

6(3x+4)+15=201

5(2x-11)+17=52


Răspuns :

6(3x+4)+15=201
18x+24+15=201
18x+39=201
18x=201-39
18x=162
x=162:18
x=9

5(2x-11)+17=52
10x-55+17=52
10x-38=52
10x=52+38
10x=90
x=90:10
x=9