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{10 la puterea 3+10 la puterea 2*[10+(5 la puterea 2-x):5]}:20la puterea 2=6
(11+11 la puterea 2+11 la puterea 3):133+x mai mic 2 la puterea 4


Răspuns :

{10³+10²*[10+(5²-x):5]}:20²=6
{10³+10²*[10+(5-x)]}:20²=6
notam pe (5-x)=t
[10³+10²*(10+t)]:20²=6
(10³+10³+10t):20²=6
(20³+10t):20²=6
20+10t=6
10t=6-20
10t=-14
t=-14/10
t=-7/5
t=5-x
-7/5=5-x
-7=25-5x
5x=25+7
x=32/5