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a+b+c=625
b-a=2
b-c=12
a,b,c=?


Răspuns :

[tex]a+b+c=625 \\ b-a=2=\ \textgreater \ a=b-2 \\ b-c=12=\ \textgreater \ c=b-12 \\ b-12+b+b-12=625 \\ 3b=625+2+12 \\ b=639:3 \\ b=213 \\ a=213-2=211 \\ c=213-12=201 \\ \\ verificare:211+213+201=625[/tex]
b-a=2 =>a=b-2
b-c=12 =>c=b-12
a+b+c=625
b-2+b+b-12=625
3b=625+2+12
3b=639
b=213
a=211
c=201
V.211+213+201=625