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Aflati numerele naturale x , y ,z stiind ca x*y =6 , y*z =21 si x*z= 14

Răspuns :

x=6/y
z=21/y
6/y*21/y=14
126/y²=14
126=14y²
y²=126/14=9
y²=9⇒y=3 sau y=-3
pt. y=3 ⇒ x*3=6⇒x=2
           ⇒ 3*z=21⇒z=7
pt. y=-3 ⇒ x=-2
             ⇒z=-7