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(4-2x)radical3 +(y+2)× radical2=0

Răspuns :

[tex](4-2x)\sqrt{3}+(y+2)\sqrt{2}=0 \\\\\\(4-2x) \sqrt{3}=0 \ \ \ \And \ \ \ (y+2)\sqrt{2}=0 \\\\ 4-2x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ y+2=0 \\\\ -2x=-4 \ \ \ |:(-2) \ \ \ \ \ \ \ \ \ \boxed{y=-2} \\\\ \boxed{x=2}[/tex]