[tex]Notatii: \\ a = 2 \sqrt{3}\;cm = apotema~triunghiului~echilateral \\ h=inaltimea~triunghiului~echilateral \\ L=latura~triunghiului~echilateral. \\ \\ Rezolvare: \\ Folosim ~formulele: \displaystyle \\ \\ a= \frac{1}{3}h ~~=\ \textgreater \ \;\;\;h=3a= 3 \times 2 \sqrt{3} =\boxed{6\sqrt{3}\;cm} \\ \\ h= \frac{L\sqrt{3}}{2} ~~=\ \textgreater \ \;\;\;L= \frac{2h}{\sqrt{3}} = \frac{2 \times 6\sqrt{3}}{\sqrt{3}} = \frac{12\sqrt{3}}{\sqrt{3}}=\boxed{12\;cm} [/tex]
