Ab=aria bazei=[tex] l^{2} [/tex] ; Al=arie laterala= [tex] \frac{Pb*ap}{2} [/tex]; At=arie totala=Al+Ab; ap=apotema piramidei; Pb=perimetrul bazei=4l; h=inaltimea; V=volumul=[tex] \frac{Ab*h}{3} [/tex]
Ab=Apatrat=[tex] l^{2} [/tex] => [tex] l^{2} [/tex]=64cm la 2 => l=8 cm => Pb=4l=4*8=32cm
Al= [tex] \frac{32*9}{2}= \frac{288}{2}=144 cm^{2} [/tex]
At=144+64=208[tex] cm^{2} [/tex]
V=64*10/3=640/3=213,33cm³
