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gaseste numarul natural ... astfel incat 3/...<.../7<4/...
justifica raspunsul.


Răspuns :

n∈N \ { 0 } ;
3 / n < n / 7 <=> 21 < [tex] n^{2} [/tex] <=> n∈{ 5, 6, 7, ....} ;
n / 7 < 4 / n<=> [tex] n^{2} [/tex] < 28 <=> n∈{ 1, 2, 3, 4, 5} ;
In final n = 5 .

Bafta !