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a) ab³/6-6x : x²-2x+1/a³b³=
b) x-1/x+1 + 1/x-1 =

de aflat DVA la raspunsuri ... va rog mult ajutatima


Răspuns :

a)  ab³ /6(1-x) ·a³b³/(x-1)² =  a^4b^6 / 6(1-x)³
daca ar fi: ab³/6(1-x) · (1-x)²/a³b³ = (1-x)/6a²
b)  (x-1)/(x+1) + 1/(x-1) = (x² -2x +1+x+1)/(x-1) = (x²-x+2)/(x-1)