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Cum se imparte numarul 1200 in parti invers proportionale cu 5/4, 5/3, 5/12, 5/6

Răspuns :

1/(5/4)k+1/(5/3)k+1/(5/12)k+1/(5/3)k=1200
4k/5+3k/5+12k/5+6k/5=1200
25k/5=1200
25k=6000
k=240
4k/5=4x240/5=192
3k/5=3x240/5=144
12k/5=12x240/5=576
6k/5=6x240/5=288