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In cate grame FeO se afla 6,023 x 10 la puterea 22 atomi de Fe ?

Răspuns :

Mas molara FeO=56+16=72g/mol

1mol.............6.023*10²³ atomi Fe
x moli............0.6023*10²³ atomi Fe
x=1*0.6023*10²³/6.023*10²³
x=0.1moli

1mol....................72g
0.1moli.....................y
y=0.1*72/1=7.2g