a=[(2,5+1,25-0,75):5+2/5]⁵=(3:5+2/5)⁵=(3/5+2/5)⁵=(5/5)⁵=1⁵=1
3,(3)=(33-3)/9=30/9=10/3
b=(7/3+7/2)·12/7-[10/3·3/1-3/1:3/10+15/10:1/4]=
=(7·2+7·3)/6·12/7-(10-3/1·10/3+15/10·4/1)=
=35·2/7-(10-10+6)=10-6=4
a<b pt.ca 1<4
2)
0,5+7/2=x+0,(3)=y²=z-(1-0,(2))
0,(3)==3/9=1/3
0,(2)=2/9
5/10+7/2=(5+7·5)/10=40/10=4
4+3/9=(4·9+3)/3=39/3=13
13²=169
169-(1-2/9)=169-(9-2)/9=169-7/9=(169x9-7)/9=(1521-7)/9=1514/9=168,(2)