[[tex] \frac{5}{2x+1} [/tex]-[tex] \frac{1}{x+1} [/tex]-[tex] \frac{1}{2x^2-x-1} [/tex]]:[tex] \frac{3x-6}{2x^2-x-1} [/tex]=[[tex] \frac{5}{2x+1} [/tex]-[tex] \frac{1}{x+1} [/tex]-[tex] \frac{1}{(x+1)(2x+1)} [/tex]]:[tex] \frac{3(x-2)}{(2x+1)(x-1)} [/tex]=[[tex] \frac{5x+5-2x-1-1}{(2x+1)(x+1)} [/tex]-[tex]] x [tex] \frac{(2x+1)(x-1)}{3(x-2)} [/tex] = [tex] \frac{3(x+1)}{(x+1)(2x+1)} [/tex] x [tex] \frac{(2x+1)(x-1)}{3(x-2)} [/tex]=[tex] \frac{x-1}{x-2} [/tex]
am adus la acelasi factor comun (x+1)(2x+1) apoi la final dupa calcule am simplificat
