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Determinati valorile lui a:
[(324+205:5-a):6]*3+127=307


Determinati nr naturale care verifica inegalitatile:
18x-14 > 2*(3x+5)
243:(x-4)>9 si x:5>2


Răspuns :

[tex][(324+205:5-a):6]*3+127=307 \\\\ \ [ (324+41-a):6 \ ]*3=307-127 \\\\ \ [ (365-a):6 \ ]*3=180 \\\\ (365-a):6 =180:3 \\\\ (365-a):6=60 \\\\ 365-a=60*6 \\\\ 365-a=360 \\\\ a=365-360 \\\\ \boxed{a=5}[/tex]



[tex]18x-14> 2(3x+5) \\\\ 18x-14>6x+10 \\\\ 18x-6x>10+14 \\\\ 12x> 24 \ |:12 \\\\ x>2 \\ x \in N \\\\ \to \boxed{x \in(3;\infty)}[/tex]



[tex]243:(x-4)>9 \ |(*243) \\\\ x-4> 2187 \\\\ x> 2187+4 \\\\ x> 2191 \\ x \in N \\\\ \to \boxed{x \in(2192;\infty)}[/tex]



[tex]x:5 >2 \ |(*5) \\\\ x>10 \\ x \in N \\\\ \to \boxed{x \in(11;\infty)} [/tex]