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cine poate sa ma ajute 25xla2-10x+1
0,25xla2+x+1
xla3-6xla2+12x-8
xla3+3xla2+3x+1


Răspuns :

0,25x²+x+1=0
Δ=b²-4ac=1²-4·0,25·1=1-1=0
x1=x2=-1/1:25/100=100/25=4

x³+3x²+3x+1=(x+1)(x²+2x+1)
x+1=0
x1=-1
x²+2x+1=0
Δ=4-4=0
x2=x3=-2/2=-1
decix1=x2=x3=-1