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( a la a doua + a+ 1 ) la a doua - ( 2a -3) la a doua + 2a  x [ 4a la a doua - ( 3a-5) x ( 3a+5 )] va rog mult !! 15 PUNCTE


Răspuns :

(a²+a+1)²-(2a-3)²+2a[4a²-(3a-5)(3a+5)]
a⁴+a³+a²+a³+a²+a+a²+a+1--(4a²-12a+9)+2a[4a²-(9a²-25)]=
a⁴+2a³+3a²+2a+1-4a²+12a-9+2a{4a²-9a²+25]=
a⁴+2a³-a²+14a-8+2a(-5a²+25)=
a⁴+2a³-a²+14a-8-10a³+50a=
a⁴-8a³-a²+64a-8