prima transformare e izocora. V1=V2, p2=5*p1(asa zice problema)
legea: [tex] \frac{p1}{T1}= \frac{p2}{T2} => T2= \frac{T1*p2}{p1}= \frac{T1*5*p1}{p1}=5*T1. [/tex]
a doua e izobara: p2=p3 V3=2*V2,dar V2=V1(din izocora 1-2)=> V3=2*V1
legea: [tex] \frac{V2}{T2}= \frac{V3}{T3} =>T3= \frac{T2*V3}{V2}= \frac{5T1*2V1}{V1}=10*T1
[/tex]
T3=10*300=3000 K
