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Determinati numerele x,ysi z stiind ca x\7=y/5=z/11si x+y+z=138

Răspuns :

x/7=y/5=z/11 ⇒ x/7=(x+y+z)/(7+5+11)=138/23=6 ⇒ x=42;
x/7=y/5 ⇒ y=30; x/7=z/11 ⇒ z=66
x=7k     y=5k   z=11k => 23k=138=>k=6=> x=42  y=30   Z=66