D : 117 = C rest C⁴
C⁴ < 117
Cautam toate numerele de forma n⁴ mai mici decat 117
A = {n ∈ N | n = k⁴ | k⁴ < 117 }
A = {0; 1; 16; 81}
=> avem 4 solutii:
C = 0; rest = 0 => D = 117 × 0 + 0 = 0
C = 1, rest = 1 => D = 117 × 1 + 1 = 118
C = 2, rest = 16 => D = 117 × 2 + 16 = 234 + 16 = 250
C = 3, rest = 81 => D = 117 × 3 + 81 = 351 + 81 = 432
