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Numerele 127,53,76 impartite la acelasi nr natural nenul n dau resturile 7,5,si respectiv 4 .Determinati numarul natural.

Răspuns :

[tex]127=n x C_{1} +7=\ \textgreater \ nx C_{1} =45[/tex]
[tex]53=nx C_{2} +3=\ \textgreater \ nx C_{2} =50[/tex]
[tex]76=nx C_{3} +4=\ \textgreater \ nx C_{3} =72[/tex]
[tex]=\ \textgreater \ [120,48,72]=24[/tex]