[tex]CH_4 + 3Cl2 -> CHCl_3 + 3HCl[/tex]
1 mol metan .................. 3 moli Cl2
3 moli metan ................. x
x=3*3= 9 moli Cl2
[tex]pV=nRT => V = \frac{9*300*0.082}{1} = 221.4 \ L \ Cl_2[/tex]
n = număr moli
T = 273+27 grade Kelvin = 300 K
R = 0.082 (constantă)