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5x[10+10x(50-50:10)]+1la puterea8x8la puterea0+1996la puterea1997x0la puterea1997 ma poate ajuta cineva ms


Răspuns :

[tex]5*[10+10*(50-50:10)]+1^8*8^0+ 1996^{1997} * 0^{1997} = \\ \\ 5*(10+10*45)+1^8*8^0+ (1996*0)^{1997} = \\ \\ 5*460+1+1+0= \\ \\ \boxed{\boxed{2302}}[/tex]
1)1997*0=0
2)0 la puterea 1997 =0
3)0+1996=1996
4)1996 la puterea 0=1
5)8*8=64
6)64 la puterea 1 =64
7)1 la puterea 64=1
5*[10+10*(50-5)]+1=5*(10+10*45)+1=5*(10+450)+1=5*460+1=2301