[tex]0,(3)=\frac{3}{9}=\frac{1}{3}\;;\\
\rightarrow\;\;(\frac{1}{3}+\frac{1}{2})*(\frac{3+2}{3})*(\frac{3}{8}*\frac{12}{7}+\frac{22}{3}*\frac{3}{11})=\;\\
...=(\frac{5}{6}*\frac{5}{3})*(\frac{9}{14}+2)=\\
...=\frac{25}{18}*\frac{37}{14}=\frac{925}{252}\approx3,67[/tex]