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Răspuns :

[tex]ED\perp(ABC)\ \ \ \ (1)[/tex]

[tex]DA\perp AB\ \ \ \ (2)[/tex]

[tex]DA, AB \subset (ABC)\ \ \ \ (3)[/tex]

[tex](1), (2), (3) \stackrel{T.3 \perp}{\Longrightarrow} EA\perp AB \Longrightarrow d(E, AB)=EA[/tex]

Aplicam T. Pitagora in triunghiul EDA si aflam EA=5 cm