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(5 intreg 3pe5-1intreg 1 pe 3):(7 intreg 7pe12 - 2 intreg 1pe4)

Răspuns :

(5+3/5 - (1+1/3)) / (7+7/12  - (2 + 1/4))

[(25+3)/5 - (3+1)/3] / [ 84+7)/12 - (8+1)/4)

(28/5 - 4/3) / ( 91/12  - 9/4)

(28x3-4x5)/15  /  (91-9x3)/12

(84-20)/15  /  (91-27)/12

(64/15)/(64/12)=(64x12)/(64x15)=12/15=4/5