[tex]a) ( \frac{2x8+3}{8} + \frac{3x24+7}{24} [/tex][tex]:( \frac{4x3+2}{3} - \frac{1x8+1}{8} [/tex][tex]= (\frac{19}{8} + \frac{79}{24} ):( \frac{15}{3} - \frac{9}{8} )= \frac{19x3+79}{24}: \frac{15x8-9x3}{24}= \frac{57+79}{24}: \frac{120-27}{24}= [tex] \frac{136}{24} : \frac{93}{24} =[tex] \frac{136}{24} x \frac{24}{93} [/tex]=[tex] \frac{136}{93} [/tex]
