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Rezolvati ecuatiil: Prin metoda mersului invers: ori = inmultire  ( paranteza rotunda
[ paranteza patrata { ecolada:
1)2x+14=59 
2) 3x+39=90
3) 5x-3,5=22,5
4) (3+x) ori 8=32
5) (9+x) : 2,5=100
6) (8+7x) ori 12-22=200
7) {[(2x+3) ori 2+ 3] ori 2+3} ori 2 +3=85. Va rog muult.



Răspuns :

1)2x=59-14=45 x=45/2
2)3x=90-39=59  x=59/3
3)5x=22.5+3.5=26 x=26/5
4)(3+x)ori8=32 3+x=32/8  x=4-3  x=1
5)(9+x)=100ori2.5  9+x=250x=250-9 x=241
6)(8+7x) ori 12=200+12  8+7x=212/12=106/6=53/3 7x=53/3-8=(53-24)/3=19/3
7){[(2x+3) ori 2+ 3] ori 2+3} ori 2 +3=85.
{[(2x+3) ori 2+ 3] ori 2+3} ori 2 =85-3=82
[(2x+3) ori 2+ 3] ori 2+3=82/2=41
[(2x+3) ori 2+ 3] ori 2=41-3=38
(2x+3) ori 2+ 3=38/2=19
(2x+3) ori 2=19-3=16
2x+3=16/2=8
2x=8-3=5
x=5/2