a) 4/(√7-√3)=4(√7+√3)/(√7-√3)(√7+√3)=4(√7+√3)/(7-3)=√7+√3
b) √3/(√3-1)=√3(√3+1)/(√3-1)(√3+1)=(3+√3)/(3-1)=(3+√3)/2
c) 1/(√7+1)=(√7-1)/(√7+1)(√7-1)=(√7-1)/(7-1)=(√7-1)/6
d) 2/(√2013+√2011)=2(√2013-√2011)/(2013-2011)=√2013+√2011
e) 6/(√7+1)=6(√7-1)/(√7+1)(√7-1)=6(√7-1)/(7-1)=√7-1
f)3/(√5-√2)=3(√5+√2)/(√5-√2)(√5+√2)=3(√5+√2)/(5-2)=3(√5+√2)/3=√5+√2
a) x/√2 = √8/3 x=√2 *√ 8/3=√16/3=4/3
b)√3/x = 2/√27 x =√3*√27/2=√81/2=9/2
c) √8/√3 = x/√27 x=√8 *√27/√3=√216/√3=√72=6√2
d) (x+1)/(√2-1) =(√2+1)/2 x+1= (√2-1)(√2+1)/2 x+1=(2-1)/2 x=1/2-1=-1/2
e) (x-1)/√5 = √15/√3 (x-1)/√5 = √5 x-1=5 x=6
f) x/√(x+2013)= √(x-2013)/1
x= √(x²-2013²)
x²= x²-2013²
0=2013²
nu are solutie
