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a)2^17 ori 2^18 - 2^34 ori 2
b) (29-2ori7)^2 ori 15^20-15^22
c) (12-3)^2 ori (6+3)^18 - 9^20
d) (4^2 : 2^2)^2 ori 4^18 :256^5
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^= la puterea


Răspuns :

A)2^17*2^18-2^34*2=2^35-2^35=0 B)(29-2*7)^2*15^20-15^22=15^2*15^20-15^22=15^22-15^22=0 C)(12-3)^2*(6+3)^18-9^20=9^2*9^18-9^20=9^20-9^20=0. D)(4^2:2^2)^2*4^18:256^5=(16:4)^2*4^18:(2^8)^5=4^2*4^18:2^40=4^20:2^40=2^40-2^40=0.