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Daca 3* x+4*y+5*z+27=59,determinati 5*z +3 * x+4* y

Răspuns :

3x+4y+5z+27=59
3x+4y+5z=59-27
3x+4y+5z=5z+3x+4y=32
5xz+3xX+4xy=3xX+4xy+5xz=59-27=32
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