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1)2,7 (1) si 2, (71) mai mare este...
2)Scrisa sub forma de interval multimea:3mai mic sau egal decat x mai mic sau egal decat 7este...
3)Suma a doua numere este 72 iar diferenta 48 aflati numerele


Răspuns :

1.
2,7(1)=(271-27)/90=244/90 =2684/990
2,(71)=(271-2)/99=269/99 =2690/990
2,(71)>2,7(1)

2.3≤x≤7
x=[3,4,5,6,7]

3.
a+b=72
a-b=48
2a=72+48
2a=120
a=60
b=72-60=12

[tex]1)2,(71)\ \textgreater \ 2,7(1)[/tex]

[tex]2)3 \leq x \leq 7 \\ x= [3,4,5,6,7][/tex]

[tex]3)a+b=72 \\ a-b=48 \\ a=? \\ b=? \\ a=48+b \\ Inlocuim:48+b+b=72 \\ 48+2b=72 \\ 2b=72-48 \\ 2b=24 \\ b=24:2 \\ b=\boxed{12} \\ a=48+12 \\ a=\boxed{60} \\ PROBA:a+b=72 \\ 60+12=72[/tex]

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