b + c + √(b² + c²) = 160
b/c = 5/6 c = 6b/5
b + 6b/5 +√(b²+ 36b²/25) = 160
11b/5 + √(61b²/25) = 160
11b/5 + b√61/5 = 160
b = 800/(11+ √61) = 800(11-√61)/60 = 40(11-√61)/3
c = 40/3 ·6/5 ·(11-√61) = 16/3 ·√(11 - √61)
b² = 1600/9 ·(182 - 22√61)
c² = 256/9 ·(182 - 22√61) a² = 1856·2/9 ·(91 - 11√61) = 3712/9 ·(91 - 11·√61)
h² = b·c/a = ....... verifica datele problemei ....... mersul rezolvarii este acesta
