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Daca x+2y=17 si y-3z=4, atunci calculati:

(2x+4y) • (x+4y-6z)


Răspuns :

Avem :
[tex](2x+4y)(x+4y-6z)= 2(x+2y)(x+2y+2y-6z)= \\ =2*17[17+2(y-3z)]=34(17+2*4)=34*25=850[/tex]