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Se considera numarul complex z=2+3i
Calculati z la a2a
Detaliat :D


Răspuns :

z^2=(2+3i)^2
z^2=4+12i-9=-5+12i
z=2+3i
z²=(2+3i)²=2²+2*2*3i+9i²
insa i²=-1
=>z²=4-9+12i=-5+12i