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media geometrica a numerelor a= 2(radical din )3 b=6(radical)3

Răspuns :

[tex]mg= \sqrt{a*b} \\ mg= \sqrt{2 \sqrt{3}*6 \sqrt{3} } \\ mg= \sqrt{12*3} mg= \sqrt{36}=6 [/tex]
[tex]M.g.= \sqrt{a\cdot b} \\\\M.g.= \sqrt{2 \sqrt{3}\cdot6 \sqrt{3} } \\\\M.g.= \sqrt{12\cdot3}\\\\\boxed{M.g.=6 }[/tex]