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2(4-√7)
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Răspuns :

2(4-√7)=8-2√7=7+1-2√7=(√7-1)²=modul de √7-1=√7-1
[tex]2(4- \sqrt{7})=2 \cdot 4- 2 \cdot \sqrt{7} =8-2 \sqrt{7} =8- \sqrt{2^2 \cdot7}=8- \sqrt{4 \cdot 7} = \\ =8- \sqrt{28} \approx8-5,29 \approx \boxed{2,71}.[/tex]