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Aflati trei numere naturale a , b , c , astfel incat a+1:(b+[tex] \frac{1}{c} [/tex])=[tex] \frac{31}{9} [/tex].
Va rog , ajutati-ma!!!!!!!


Răspuns :

a+1÷(b+1/c)=31/9<=>a+1÷(bc+1)/c=31/9 <=>a+c/(bc+1)=31/9<=>(abc+a+c)/(bc+1)= 31/9<=>9abc+9a+9c=31bc+31<=>9abc-31bc+9a+9c=31=9a(bc+1)-c(31b+1)