1. Are rolul de a produce PbSO4 ce are alt rol.
2 PbO2 + 2 H2SO4 → 2 PbSO4 + 2 H2O + O2
2.10ml NaOH de concentratie 1M
MNaOh = ANa + AO + AH= 23+16+1= 40g/mol
¶(densitate) NaOH = 2.13g/cm3
VNaOH= 40g/2.13g
VNaOH= 18.77ml
Vsolutie initiala= 10+18.77ml
Vs.i.= 28.77ml
V apa adaugata= 250-28.77ml= 221.23ml
Vapa totala= 221.23ml+10ml= 231.23ml
Vsolutiei finale= 231.23+18.77ml= 232ml
C molara finala= 1M NaOh/232ml