1)din triunghiul dreptunghic ADB, sinB=AD/AB⇒12/13=36/AB⇒AB=39
BD=radical(39^2-36^2)=15 cm
Din triunghiul dreptunghic ADC, cosC=DC/AC⇒DC=AC*cosC
AC^2-36^2=AC^2*9/25
25AC^2-9AC^2=36^2*25
16AC^2=36^2*25⇒AC^2=36^2*25/16⇒AC=36*5/4=45
Deci, DC=45*3/5=27
atunci BC=BD+DC=15+27=42
AΔ=1/2BC*AD=1/2*42*36=756 cm^2
2)AΔ=1/2*AB*AC*sinA
AΔ=1/2*60*80*1/2=1200 cm^2