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[tex] \frac x2+ \frac 15 \leq \frac310x-7+1[/tex] rapid va rog! dau coronita cui rezolva



Răspuns :

[tex] \frac{5x+2}{10} \leq \frac{3}{10} x-6 5x+2 \leq 3x-60 5x-2x \leq -62 3x \leq -62 x \leq - \frac{62}{3} [/tex]