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Stiind ca x=5 si y+z==14, calculati: a) x+2y+2z si b) 5x+3y+3z

Răspuns :

a. 5+2·14=5+28=33;
b. 5·5+3·7=25+21=46;
x=5 ;y+z=14 a).x+2y+2z=x+2(y+z)=5+2×14=5+28=33. b).5x+3y+3z=5x+4(y+z)=5×5+4×14=25+56= 81.