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La clorurarea catalitica a toluenului se obtine o masa de reactie de 1391,5 grame formata din 36,36% o-clortoluen ,27,27% p-clortoluen ,23,14% 2,4-diclortoluen si 13,22% toluen nereactionat .Care este conversia totala si randamentu procesului?

Răspuns :

1391,5g amestec..............100%
xg orto............................36,36%
yg para...........................27,27%
zg dicloro.......................23,14%
tg nereactionat..............13,22%
x=506g o-cloro toluen
y=379,5g p-cloro toluen
z=322g diclorotoluen
t=184g toluen nereactionat
1mol....................126,5g
C7H8 + Cl2 -> o-C7H7Cl + HCl
a=4moli...............506g
1mol....................126,5g
C7H8 + Cl2 -> p-C7H7Cl + HCl
b=3moli...............379,5g
1mol...................161g
C7H8 + Cl2 -> C7H6Cl2 + 2HCl
c=2moli.............322g
1mol.......92g
C7H8 -> C7H8
d=2moli..184g
Ct/100=ntrans/nintrodus=9/11 => Ct=81,81%
randamentul=Ct=81,81%