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Cum se rezolva inecuatia 2(x+1) < 0

Răspuns :

2(x+1) < 0  / : 2
x+1 < 0
x < -1
x ∈ (- ∞ , - 1)  => S= ( - ∞ , -1)

2(x+1)<0 / -1 2x < -1/:2 2 X= -- -1 2 X=- -- 1 X€z¦ --> x= { -2 ; -1; 0 ;1 ;2 ... } Asta am facut astazi la scoala !