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sa se arate ca
(√3 +√2 +1)^2 = 2[(1+√2)(1+√3) + 2]


Răspuns :

(√3 +√2 +1)^2 = 2[(1+√2)(1+√3) + 2]=
2√3+2√2+2=2(1+√3+√2+√6)+2
2√3+2√2+2=2+2√3+2√2+2√6+2
2√3-2√3-2√2-2√6=2-2
2√4=0
(a+b+c)² = a²+b² +c² +2ab+2ac+2bc

(√3 +√2 +1)² = 3+2+1+ 2√6 +2√3 +2√2 = 6 + 2( √6 +√3 +√2) =
= 6 + 2[√3(1+√2) +√2] = 2[ 3 + √3(1+√2) +√2]= 2[ 1+√2 +√3(1+√2) + 2] =
=2[(1+√2)(1+√3) +2]