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”i la purea 69 ” rezolvarea

Răspuns :

      
[tex]i^{69}=i^{(68+1)}=i^{68}*i^1 = i^{(2*34)}*i = \\ \\ = (i^{2})^{34}*i=(-1)^{34}*i =(-1)^{(2*17)}*i = \\ \\ =((-1)^{2})^{17}*i = 1^{17}*i = 1*i = \boxed{i}[/tex]