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x+y<168
x:y=2 rest 41


Răspuns :

x=2y+41
inlocuim in x+y<168
2y+41+y<168
3y<168-41
y<127/3
y<42,(3)
x=2·127/3+41
x=(254+41·3)/3=377/3
x=125,(6)