👤

Cum se descompune x^2-3x+2 ?

Răspuns :

[tex] x^{2} -3x+2=0 \\ \Delta=9-4*1*2=9-8=1 \\ x_{1}= \frac{-b- \sqrt{\Delta} }{2a} = \frac{3-1}{2}=1 \\ x_{2} = \frac{-b+ \sqrt{\Delta} }{2a} = \frac{3+1}{2}=2 \\ a x^{2} +bx+c=a(x- x_{1} )(x- x_{2} ) \\ x^{2} -3x+2=(x-1)(x-2)[/tex]