Acidul oleic: C18H34O2 (ii scrii cu formula de structura, daca e problema de BAC)
282g............................284g
C18H34O2 + H2 -> C18H36O2
564g............................x=?
564*284/282=568g acid stearic (la un randament de 100%)
randamentul = masa practica*100/masa teoretica = 284*100/568 = 50%