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Calculați : 
[tex] \frac{1}{2} [/tex] + 1,1(6) + 1,(3) : [ 0,(6)] la puterea a 2-a


Răspuns :

[tex]\dfrac12+\dfrac{116-11}{90}+\dfrac{13-1}{9}:\left(\dfrac69\right)^2=\dfrac12+\dfrac76+\dfrac43\cdot\dfrac94=\dfrac12+\dfrac76+3=[/tex]

[tex]=\dfrac{3+7+18}{6}=\dfrac{28}{6}=\dfrac{14}{3}=4\dfrac23=4,(6)[/tex]